Question

A large explosion causes wood and metal debris to rise vertically into the air with an initial velocity of 96 feet per second. The function h(t) = 96 t − 16 t 2 gives the height of the falling debris above the ground, in feet, t seconds after the explosion. A) Use the given function to find the height of the debris 2 second(s) after the explosion: Answer: After 2 second(s), the height is 112 Incorrect feet.

Answer 1

Answer:

the height after 2 seconds will be 128 feet

Step-by-step explanation:

Data provided in the question:

Initial velocity = 96 feet per second

The function of height of falling debris above the ground is given as:

h(t) = 96t - 16t²

A) To find height after time t = 2 seconds

substituting the value of time in the above function, we get

h(t) = 96 × 2 - 16 × 2²

or

h(t) = 192 - 16 × 4

or

h(t) = 192 - 64

or

h(t) = 128 feet

Hence,

the height after 2 seconds will be 128 feet

Answer 2

The height of the debris 2 second(s) after the explosion is 128 ft.

Step-by-step explanation:

Given :

Initial velocity = 96 ft/sec

The function of height of falling debris above the ground is,

$h(t) = 96t-16t^2$

Solution :

The height of the debris 2 seconds after the explosion is

$h(t) = (96\times 2 ) - (16\times 2^2)$

$\rm h(t) = 128\; ft$

The height of the debris 2 seconds after the explosion is 128 ft.

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