Answer: D) 0.733.
Step-by-step explanation:
Let C denotes the number of employees having college degree and S denote the number of employees are single.
We are given ,
Total = 600 , n(C)=400 , n(S)=100 , n(C∩S)=60
Then,
[tex]n(C\cup S)=n(C)+n(S)-n(C\cap S)\\\\=400+100-60=440[/tex]
Now, the probability that an employee of the company is single or has a college degree is
[tex]P(C\cup S)=\dfrac{n(C\cup S)}{\text{Total}}\\\\=\dfrac{440}{600}=0.733333333\approx0.733[/tex]
Hence, the probability that an employee of the company is single or has a college degree is 0.733