Answer:
The equation of the line (-1/2, 3) and (0, 0) is y = -6x
Solution:
Given, two points are ([tex]\frac{-1}{2}[/tex] , 3) and (0, 0)
We have to find the line equation that passes through the given two points.
Now, we know that, line equation that passes through [tex]\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)[/tex] is given by:
[tex]y-y_{1}=\left(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\right)\left(x-x_{1}\right)[/tex]
Here in our problem, [tex]x_{1}=0, y_{1}=0, x_{2}= \frac{-1}{2} \text { and } y_{2}=3[/tex]
Substitute these values in above formula.
[tex]y-0=\left(\frac{3-0}{\frac{-1}{2}-0}\right)(x-0) \rightarrow y=\frac{3}{\frac{-1}{2}} \times x \\\\\rightarrow y=3 \times\left(\frac{-2}{1}\right) \times x \rightarrow y=-6 x[/tex]
Hence the equation of the line (-1/2, 3) and (0, 0) is y = -6x