Answer:It would be 9 times as great as the value it was at 10 mph.
Explanation:For the answer I gave above to be true, I had to assume the car follows the exact same path at the new speed.
The usual formula for centripetal acceleration is:
F
c
=
m
⋅
v
2
r
However I will revise the format to group m and r away from the area of interest:
F
c
=
(
m
r
)
⋅
v
2
For 10 mph:
F
c
=
(
m
r
)
⋅
v
2
F
c
=
(
m
r
)
⋅
(
10
m
p
h
)
2
=
(
m
r
)
⋅
100
(
m
p
h
)
2
For 30 mph:
F
c
=
(
m
r
)
⋅
v
2
F
c
=
(
m
r
)
⋅
(
30
m
p
h
)
2
=
(
m
r
)
⋅
900
(
m
p
h
)
2
Notice that the factor that had been 100 becomes 900.
Answer:
It would be 9 times as great as the value it was at 10 mph.
Explanation:
hope this helps
