Question

Write an equation of a line parallel to y =2/3x - 4 that passes through the point (-6, 1). Y=2/3x+5 Y=-2/3x-10 y=-3/2x-8 Y=2/3x-3

Answer 1

The equation of line parallel to given line is:

$y=\frac{2}{3}x+5$

Further explanation:

When the equation of line is given in point-slope form, the coefficient of x is the slope of the line.

The general form of equation of line in point-slope form is:

$y=mx+b$

Here m is the slope.

Given

$y=\frac{2}{3}x-4$

The slope of given line will be 2/3

As the new line is parallel to the given line, both lines will have same slope.

So,

The equation of new line will be:

$y=\frac{2}{3}x+b$

We have to find the value of b, for that we will put the ordered pair in the equation from which the line passes

So,

$1=\frac{2}{3}(-6)+b\\1=-4+b\\b=1+4\\b=5$

Putting the values of m and b gives us:

$y=\frac{2}{3}x+5$

Keywords: Equation of line, Point-slope form of line

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