From her window, Carmella looks up to the top of a neighboring building at an angle of 46°. Her
angle of depression to the bottom of the building is 25°
The neighboring building is 180 feet away from the building Carmella is in.
How tall is the neighboring building?
round your answer to the nearest tenth of a foot

Respuesta :

Answer:

[tex]270.3\ ft[/tex]

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the right triangle ADE

Find the value of h1

See the attached figure

h1=AD

[tex]tan(25\°)=\frac{h_1}{180}[/tex]

Solve for h1

[tex]h_1=(180)tan(25\°)\\h_1=83.94\ ft[/tex]

step 2

In the right triangle ABC

Find the value of h2

See the attached figure

h2=BC

[tex]tan(46\°)=\frac{h_2}{180}[/tex]

Solve for h2

[tex]h_2=(180)tan(46\°)\\h_2=186.40\ ft[/tex]

step 3

Find the height of the neighboring building

we know that

The height of the neighboring building is equal to

[tex]h=h_1+h_2[/tex]

substitute the values

[tex]h=83.94+186.40=270.34\ ft[/tex]

Round to the nearest tenth of a foot

[tex]h=270.3\ ft[/tex]

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