Answer:
[tex]270.3\ ft[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
In the right triangle ADE
Find the value of h1
See the attached figure
h1=AD
[tex]tan(25\°)=\frac{h_1}{180}[/tex]
Solve for h1
[tex]h_1=(180)tan(25\°)\\h_1=83.94\ ft[/tex]
step 2
In the right triangle ABC
Find the value of h2
See the attached figure
h2=BC
[tex]tan(46\°)=\frac{h_2}{180}[/tex]
Solve for h2
[tex]h_2=(180)tan(46\°)\\h_2=186.40\ ft[/tex]
step 3
Find the height of the neighboring building
we know that
The height of the neighboring building is equal to
[tex]h=h_1+h_2[/tex]
substitute the values
[tex]h=83.94+186.40=270.34\ ft[/tex]
Round to the nearest tenth of a foot
[tex]h=270.3\ ft[/tex]