Question

A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 25.0 m/s and returns the shot with the ball traveling horizontally at 39.0 m/s in the opposite direction. (Assume the initial direction of the ball is in the −x direction.

Answer 1

The impulse delivered to the ball is 3.84 N.

Explanation:

The impulse exerted on an object is equal to the change in momentum of the object, therefore:

$I=\Delta p = m(v-u)$

where:

m is the mass of the object

v is the final velocity

u is the initial velocity

For the ball in the problem, assuming the initial direction of the ball as negative direction, we have:

u = -25.0 m/s

v = 39.0 m/s

m = 0.06 kg

Therefore, the impulse exerted on the ball is

$I=(0.06)(39.0-(-25.0))=3.84 Ns$

Learn more about impulse and change in momentum here:

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