The equation of a line that is parallel to y = 0.62 x + 3 and that
passes through the point (-3 , -5) is y = 0.62 x - 3.14
Step-by-step explanation:
Parallel lines have:
1. Same slopes
2. Different y-intercept
The slope-intercept form of the linear equation is y = m x + c, where
m is the slope of the line and c is the y-intercept
We need to find the equation of the line that is parallel to
y = 0.62 x + 3 and passes through the point (-3 , -5)
∵ The two lines are parallel
∴ Their slopes are equal
∵ The equation of the given line is y = 0.62 x + 3
∵ The form of the equation is y = m x + c
∴ m = 0.62
∴ The slope of the line is 0.62
∵ The equation of the line is y = mx + c
∵ m = 0.62
∴ The equation of the line is y = 0.62 x + c
- To find c substitute x and y in the equation by the coordinates of
a point lies on the line
∵ The line passes through the point (-3 , -5)
∴ x = -3 , y = -5
∴ -5 = 0.62(-3) + c
∴ -5 = -1.86 + c
- Add 1.86 for both sides
∴ c = -3.14
∴ The equation of the line is y = 0.62 x + (-3.14)
∴ The equation of the line is y = 0.62 x - 3.14
The equation of a line that is parallel to y = 0.62 x + 3 and that
passes through the point (-3 , -5) is y = 0.62 x - 3.14
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