Question

Commercial airplanes are sometimes pushed out of the passenger loading area by a tractor. The 1800 kg tractor exerts a force of 1.95 104 N backward on the pavement, and the system experiences forces resisting motion that total 2400 N. If the acceleration is 0.240 m/s2, what is the mass of the airplane in kilograms? Calculate the force (in N) exerted by the tractor on the airplane, assuming 2100 N of the friction is experienced by the airplane.

Answer 1

Answer:

Explanation:

Given

mass of tractor=1800 kg

Force(F)$=1.95\times 10^4 N$

Resisting Force=2400 N

acceleration $(a)=0.24 m/s^2$

Let m be the mass of airplane

$F-2400=(m+1800)\times 0.24$

$19500-2400=(m+1800)\times 0.24$

m=69450 kg

(b)If friction force experienced by airplane is 2100 N then

$F_{net}=ma$

$F_0-2100=69450\times a$

$F_0=2100+69450\times 0.24$

$F_0=18768 N$