A machine is available 10 hours a day. Each part takes 90 minutes to fabricate and 10 minutes to setup. 10% of the parts made are defective and must go through the machine again to be reworked, during which both setup and fabrication have to be performed again. The machine is idle for any unused time. On average, 5 good parts are made each day. What is the overall equipment effectiveness of the machine?

Respuesta :

Answer:

Effectiveness = 0.75

Explanation:

Availability time for a each day = 10 hr = 600 minutes

Total time for fabricating is given as 90 minutes'

Total time to set up one part 10 minutes

Total parts made in each single day 5

Percentage of defective part 10%

Total production time for a single part = setup time  + fabricated time

                                                                 = 10+ 90 = 100 min

Production time for 5 part =5 × 100 = 500 minutes

Total number of defective parts =  10% of 5  =  0.5 parts

Time to replaced defective = 0.5  × 100 = 50 min

Value added time = 500 - 50 = 450 min

Effectiveness  is given as

Effectiveness  [tex]= \frac{value\ added\ time}{ total\ time\ taken}[/tex]

Effectiveness [tex]= \frac{450}{600} = 0.75[/tex]

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