Question

What are the solutions of 2x2 + 3x = −5?


the quantity negative 3 plus or minus i square root of 31 all over 4

the quantity negative 3 plus or minus 7i all over 4

the quantity negative 3 plus or minus i square root of 19 all over 4

the quantity negative 3 plus or minus 4i all over 4

Answer 1

Answer:a

Step-by-step explanation:

Given

$2x^2+3x=-5$

or it can be write as

$2x^2+3x+5=0$

Finding discriminant of equation

$D=b^2-4ac$

$D=3^2-4\times 2\times 5$

D=9-40=-31

D<0 therefore there are no real roots

so

$x=\frac{-3\pm \sqrt{3^2-4\times 2\times 5}}{2\times 2}$

$x=\frac{-3+i\sqrt{31}}{4} and \frac{-3 -i\sqrt{31}}{4}$