Kinematics practice problems Answers: 1. Georgia is jogging with a velocity of 4 m/s when she accelerates at 2 m/s2 for 3 seconds. How fast is Georgia running now? 2. In a football game, running back is at the 10 yard line and running up the field towards the 50 yard line, and runs for 3 seconds at 8 yd/s. What is his current position (in yards)? 3. A cat is moving at 18 m/s when it accelerates at 4 m/s2 for 2 seconds. What is his new velocity?

Respuesta :

Explanation:

It is given that,

1. Initial speed of Georgia, u = 4 m/s

Acceleration of Georgia, [tex]a=2\ m/s^2[/tex]

Time taken, t = 3 s

Let v is the final speed of Georgia. It can be calculated as :

[tex]v=u+at[/tex]

[tex]v=4+2\times 3[/tex]

v = 10 m/s

2. Initial distance covered, x = 10 yard

Time taken by the person, t = 3 s

Speed, v = 8 yd/s

Distance covered by the runner,

[tex]d=v\times t[/tex]

[tex]d=8\times 3[/tex]

d = 24 yards

So, the current position of runner is, 10 + 24 yards = 34 yards

3. Initial speed of the cat, u = 18 m/s

Acceleration of the cat, [tex]a=4\ m/s^2[/tex]

Time taken, t = 2 s

Let v is his new velocity. It can be calculated as :

[tex]v=u+at[/tex]

[tex]v=18+4\times 2[/tex]

v = 26 m/s

Hence, this is the required solution.

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