Answer:
The function is not defined for x=0, so the given function has no y-intercept.
x-intercept of the function is 9.
The function has no vertical or horizontal asymptote.
The function has whole at x=0.
Step-by-step explanation:
The given function is
[tex]f(x)=\dfrac{x^2-9x}{x}[/tex]
[tex]f(x)=\dfrac{x^2}{x}-\dfrac{9x}{x}[/tex]
[tex]f(x)=x-9[/tex]
It is a linear function and graph of a linear function is a straight line.
The function is not defined for x=0, so the given function has no y-intercept.
Substitute f(x)=0 to find the x-intercept.
[tex]0=x-9[/tex]
[tex]9=x[/tex]
x-intercept of the function is 9.
At x=1,
[tex]f(1)=1-9=-8[/tex]
Connect (9,0) and (1,-8) by a straight line.
After cancellation, the given function is a linear function. So, the function has no vertical or horizontal asymptote.
Equate the cancelled factor equal to 0, to find the whole.
[tex]x=0[/tex]
Therefore, the function has whole at x=0.