Question

please help asap, thank youuu

Answer 1

Hence the correct final answer is:

$\frac{4y^3}{x^3}$

Further explanation:

Given

$Line\ 1: \frac{4}{1}.\frac{x^{-2}}{1}.\frac{1}{x}.\frac{y}{1}.\frac{1}{y^{-2}}$

The student made the mistake in line two. There was no need to move 4 in the first term, from numerator to denominator

The correct line 2 will be:

$Line\ 2: \frac{4}{1}.\frac{1}{x^2}.\frac{1}{x}.\frac{y}{1}.\frac{y^{2}}{1}}\\Line\ 3: \frac{4y^3}{x^3}$

Hence the correct final answer is:

$\frac{4y^3}{x^3}$

Keywords: Fractions, exponents

Learn more about exponents at:

• brainly.com/question/5014716
• brainly.com/question/5147732

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