Question

A 1756 kg car comes to a stop in 2 seconds from a speed of 45 m/s. What was the braking force of the car?

Answer 1

Explanation:

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Answer 2

The braking force of the car  is 39510 N

Explanation

Given:

Mass  of the car = 1756 kg

Time s= seconds

Initial velocity u = 45 m/s

To find:

The braking force of the car=?

Solution:

The equation of motion is v=u+at

Where  

u = initial veloctity

v = final velocity

a = acceleration

t = time

let the final velocity v=0 m/s

substituting the values  we get

v=u+at

$0=45+(a)(2)$

$-45=2a$

$a=\frac{-45}{2}$

$a=-22.5m/s$

 Now according to Newton's second law of the braking force can be calculated as

|F|=|m| |a|

F=|1756| |-22.5|

F= 1756*22.5

F=39510 N