Question

A student has $1 bills and $5 bills in his wallet. He had a total of 15 bills that are worth $47. How many of each type does he have?

Answer 1

Total number of $1 bills=7

Total number of $5 bills=8

Further explanation:

Given

Let x be the number of $1 bills

and

y be the number of $5 bills

Then according to the given statements

x+y=15

x+5y=47

From first equation:

$x+y=15\\x=15-y$

Putting x=15-y in second equation

$x+5y=47\\15-y+5y=47\\4y=47-15\\4y=32\\\frac{4y}{4}=\frac{32}{4}\\y=8$

Putting y=8 in first equation

$x+8=15\\x=15-8\\x=7$

Hence,

Total number of $1 bills=7

Total number of $5 bills=8

Keywords: Linear equations, Substitution method

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