Answer:
After subtraction expression will be[tex]\frac{-2x-5}{(x+1)(x+2)}[/tex]
Step-by-step explanation:
We have given expression [tex]\frac{x}{x+2}-\frac{3}{x+1}[/tex]
We have to subtract this
We know that for subtraction of fraction first we have to take L.C.M of denominator
So L.C.M of (x+2) and (x+1) will be (x+2) (x+1)
So [tex]\frac{x}{x+2}-\frac{3}{x+1}=\frac{x+1-3(x+2)}{(x+2)(x+1)}=\frac{x+1-3x-6}{(x+2)(x+1)}=\frac{-2x-5}{(x+1)(x+2)}[/tex]