Question

If 9\geq4x+19≥4x+19, is greater than or equal to, 4, x, plus, 1, which inequality represents the possible range of values of 12x+312x+312, x, plus, 3? Choose 1 answer: 12x+3\geq1712x+3≥1712, x, plus, 3, is greater than or equal to, 17 12x+3\leq1712x+3≤1712, x, plus, 3, is less than or equal to, 17 12x+3\geq2712x+3≥2712, x, plus, 3, is greater than or equal to, 27 12x+3\leq2712x+3≤2712, x, plus, 3, is less than or equal to, 27

Answer 1

Answer:

$12x + 3\leq 27$

Step-by-step explanation:

∵ 12x + 3 = 3 × 4x + 3 = 3( 4x + 1 ) ( Since, HCF(12, 3) = 3 )

Given inequality,

$9\geq 4x+1$

∵ ∵ a > b ⇒ $ca > cb$ if c > 0,

a > b ⇒ $ca < cb$ if c < 0,

$\implies 3(9) \geq 3(4x + 1)$

$27 \geq 12x + 3$

$\implies 12x + 3\leq 27$

Hence, LAST option is correct.