Answer with Step-by-step explanation:
We are given that a function
[tex]m(x)=\frac{x}{x-1}[/tex]
a.We have to find the inverse of m.
Suppose, [tex]y=m(x)=\frac{x}{x-1}[/tex]
[tex]yx-y=x[/tex]
[tex]yx-x=y[/tex]
[tex]x(y-1)=y[/tex]
[tex]x=\frac{y}{y-1}[/tex]
Replace x by y and y by x
[tex]y=\frac{x}{x-1}[/tex]
Substitute [tex]y=m^{-1}(x)[/tex]
[tex]g(x)=m^{-1}(x)=\frac{x}{x-1}[/tex]
b.When the inverse function of given function is [tex]\frac{x}{x-1}[/tex]
Then , we get fog(x)=[tex]f(g(x))=\frac{\frac{x}{x-1}}{\frac{x}{x-1}-1}[/tex]
[tex]fog(x)=\frac{x}{x-x+1}=x=I(x)[/tex]
When f and g are inverse to each other then fog(x)=Identity function.
c.If f(x)=x
It is self inverse function.