Question

ASAP A virus has a volume of approximately 4.7x10^-14 cubic centimeters. Calculate the estimated volume of 4.1x10^16 viruses.


1.927 ×103


19.27 ×1031


1.927 ×102


1.927 ×1031

Answer 1

Hence, the volume of 4.1x10^16 viruses is:

$1.927*10^3\ cm^3$

Further explanation:

Given

$Volume\ of\ one\ virus=4.7*10^{-14}\ cm^3$

$Volume\ of\ 4.7*10^{16}\ viruses=?$

To find the volume of given viruses, volume of one virus will be multiplied to the number of viruses

So,

$Volume\ of\ 4.1*10^{16}\ viruses= (4.7*10^{-14})*(4.1*10^{16})$

When two numbers with exponents have to be multiplied, their powers are added and number are multiplied.

$V=(4.7*4.1)*(10^{-14+16})\\=(19.27)*(10^2)\\=19.27*10^2\\=1.927*10*10^2\\=1.927*10^{1+2}\\=1.927*10^3$

Hence, the volume of 4.1x10^16 viruses is:

$1.927*10^3\ cm^3$

Keywords: Volume, Exponents

Learn more about exponents at:

• brainly.com/question/1970035
• brainly.com/question/210834

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