Answer:
There are 5 boxes on the tenth row.
Step-by-step explanation:
We are given the following information in the question:
Each row of tissues has 2 fewer boxes than the row below.
The first row has 23 boxes of tissues.
23, 21, 19, 17,...
a) Let f(x) be the function that represent the arithmetic sequence.
Then,
[tex]f(x) = x-2[/tex], where x is the number of boxes in previous rows.
b) Comparing the given sequence to an arithmetic progression, we have
First term,a = 10
Common difference,d = -2
[tex]a_n = a + (n-1)d\\a_{10} = 23 + (10-1)(-2) = 23-18 =5[/tex]
Thus, there are 5 boxes on the tenth row.