Respuesta :

Answer:

[tex]\sqrt{119+120 i}=\pm (12.24+i 4.90)[/tex]

Step-by-step explanation:

Given

z = 119 + 120 i

Let [tex]\sqrt{119+120 i}=p+iq[/tex]

Squaring both sides

[tex]119+120 i=p^2-q^2+2ipq[/tex]

Comparing real and imaginary part

Re(LHS)=Re(RHS)

[tex]119=p^2-q^2[/tex]...........................(1)

comparing Im(LHS)=Im(RHS)

120=2pq

[tex]q=\frac{60}{p}[/tex]

Substitute q in 1

[tex]119=p^2-(\frac{60}{p})^2[/tex]

[tex]p^4-119p^2-(68)^2=0[/tex]

Let [tex]x=p^2[/tex]

[tex]x^2-119x-4624=0[/tex]

[tex]x=\dfrac{119\pm \sqrt{119^2+4\times 4624}}{2}[/tex]

[tex]x=\frac{119\pm 180.71}{2}[/tex]

we take only Positive value because [tex]p^2=x[/tex]

x=149.85  

[tex]p^2=149.85[/tex]

thus [tex]p=\pm 12.24[/tex]

[tex]q=\pm 4.90[/tex]

thus,

[tex]\sqrt{119+120 i}=\pm (12.24+i 4.90)[/tex]

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