Question

What is the 4th term of the geometric sequence with $a_{1}$ = 5 and ratio (multiplier) = -3?

Answer 1

Answer:

The 4th term of the geometric sequence with  = 5 and ratio (multiplier) = -3 is -135

Solution:

Given that, first term a of a G.P = 5 and common ratio ( r )  = -3 for an geometric progression.

We have to find the 4th term of the above given geometric progression

We know that, nth term of an G.P is given by

$t_{n}=a \cdot r^{n-1}$

So, now, 4th term is

$\begin{aligned} t_{4} &=5 \times(-3)^{4-1} \\ t_{4} &=5 \times(-3)^{3} \\ t_{4} &=5 \times(-27) \end{aligned}$

$t_{4}=-135$

hence, the 4th term of the given G.P is -135