Question

What is the magnitude of the acceleration of a skydiver who is currently falling at four-fifths his eventual terminal speed?

Answer 1

Answer:

3.5316 m/s²

Explanation:

At terminal velocity v acceleration

a = g

where,

g = Acceleration due to gravity  = 9.81 m/s²

$ma=mg-m\left(\frac{4}{5}\right)^2g\\\Rightarrow a=g(1-\frac{16}{25})\\\Rightarrow a=\frac{9}{25}g\\\Rightarrow a=\frac{9}{25}\times 9.81\\\Rightarrow a=3.5316\ m/s^2$

The acceleration of the skydiver who is currently falling at four-fifths his eventual terminal speed is 3.5316 m/s²