Answer:
Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26
Solution:
Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7
Standard form of line passing through point ( a , b ) and having slope m is given by
(y – b) = m ( x – a) --------(1)
In our case given point is ( -2 , 4 ) and slope is -1/7 that means
a = -2 , b = 4 , m = -(1/7)
On substituting given value of a , b and m is equation (1) we get
[tex](y-4)=\left(-\frac{1}{7}\right)(x-(-2))[/tex]
[tex]=>(y-4)=\left(-\frac{1}{7}\right)(x+2)[/tex]
=> 7( y - 4 ) = -x – 2
=> 7y + x = -2 + 28
=> x + 7y = 26
Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26
