Question

Write the sum or difference in the standard form a + bi.
( 4 - 2i) + ( 9 + 6i)

13 - 4i
13 + 4i
-13 - 4i
-5 + 8i

Answer 1

Answer:

Sum = 13+ 4i            Difference = -5 - 8i

Step-by-step explanation:

Given complex number as (4 -2i)  and  (9 + 6i)

Sum of these complex number is

(4 -2i)  + (9 + 6i) = ( 4 +9) + (6i -2i)

                           = 13 +4i

Difference of these complex number is

(4 -2i)  - (9 + 6i) = (4 -9) - (2i +6i)

                        = -5 - 8i

Hence the sum and Difference of given complex numbers are

Sum = 13+ 4i            Difference = -5 - 8i              Answer