Respuesta :
Answer:
B. {−21, −7, 7, 21}
Step-by-step explanation:
Choices for this question are
A. {−21, 21}
B. {−21, −7, 7, 21}
C. {−14, 0, 14}
D. {−21, −14, −7}
We need to pick a set that has elements of Z and they are odd number and multiples of 7.
Therefore, the right answer is
B. {−21, −7, 7, 21}
Because, this set includes all elements of set Z that are odds and multiples of 7.
The choice A doesn't include -7 and 7, which has to.
Choice C and D includes even numbers.
The set that has elements of set Z that are odd numbers and are also a multiple of 7 is:
{−21, −7, 7, 21}.
Let's recall what an odd number that is a multiple of 7 is:
- An odd number is an integer that you cannot divide into two without a remainder.
- If you divide an odd number by 2, you will always have a remainder
- A multiple of 7 is any number you will get when you multiply 7 and another number.
- Let's consider the given set of Z:
Z = {-21, -14, -7, 0, 7, 14, 21}
In the set given we have the following:
- -21, -7, 7, 21 are all odd numbers
- -21, -14, -7, 7, 14, and 21 are all multiples of 7.
However, -21, -7, 7, and 21 are all both multiples of 7 and also are odd numbers.
Therefore, the set that has elements of set Z that are both odd numbers and are also multiples of 7 is:
{−21, −7, 7, 21}
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