A clown has 21 animals that he uses in his magic show. Some of the animals are birds, the rest are bunnies. The animals have a total of 76 legs. how many of each animal does he have?

Respuesta :

Answer:

The answer to your question is:

bunnies = 17 bunnies

birds = 4 birds

Step-by-step explanation:

Data

animals = 21

birds = b = ?

bunnies = u = ?

total legs = 76

Process

                                 b + u = 21               -----(1)

                                2b + 4u = 76           ----- (2)

Solve by elimination

                              -2b - 2u = -42

                               2b + 4u = 76

                                       2u = 34

                                         u = 17 bunnies

                                b + 17 = 21

                                b = 21 - 17

                                b = 4 birds

We know bunnies have 4 legs. Let’s use the equation 4a, a being the number of bunnies and 4 being the number of legs each
Birds have 2 legs. let’s use the equation 2b.
There are 21 animals.

4a + 2b = 76, and a+b = 21

if u divide 76 by 4 you get 19.
however, you need 21 animals so you can replace 2 of them so
4 x 17 (19-2) and replace the eight legs with 4 birds

17 bunnies and 4 birds equals
68 + 8 = 76 legs and
17 + 4 = 21 animals


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