Question

The sum of the ages of Mr Lee and his son is 53 now. 4 years ago, the age of Mr Lee was 4 times that of his son. Find their ages now.

Must be answered with an equation. Any help is appreciated :)

Answer 1

Answer:

Now, Mr Lee's age is 40 years, his son's age is 13 years.

Step-by-step explanation:

4 years ago:

Son's age = x years

Mr. Lee age = 4x years

Now:

Son's age = x + 4 years

Mr. Lee age = 4x + 4 years

The sum of the ages of Mr Lee and his son is 53 now, so

$x+4+4x+4=53\\ \\x+4x=53-4-4\\ \\5x=53-8\\ \\5x=45\\ \\x=9\\ \\4x=36\\ \\x+4=9+4=13\\ \\4x+4=36+4=40$

Now, Mr Lee's age is 40 years, his son's age is 13 years.

Answer 2

Answer:

Mr.Lee age = 40 years and his son age = 13 years

Explanation:

Let x & y be the ages of Mr.Lee and his son.

as per the question

x+y=53 ---------------------------------------- (1)eq.

4 years ago,

The relation given as per the problem (x-4)=4(y-4)

that implies x-4y= -12 -----------------------------(2) eq.

x=53-y from equation (1);

substitute x in equation - (2) ;

53-y-4y=-12;

53+12 = 5y ;

65=5y;

y+$65/5$= 13 years;

x=53-13 = 40 years;

Therefore Mr.Lee age = 40 years and his son age = 13 years