Answer:
[tex]x = \sqrt{3} [/tex]
[tex]x = - \frac{ \sqrt{6} }{2} [/tex]
Step-by-step explanation:
To solve, split the middle term like you would a quadratic.
ac (2*-9) should be able to have multiples that add into b (-3).
Which, it does: -6 and 3.
2x^4-6x^2+3x^2-9. Now, you can factor.
2x^2(x^2-3)+3(x^2-3)
You now have 2 factors to put together. The two in parentheses combine into one and the two outer terms become their own.
(2x^2+3)(x^2-3)
Now, set both equations equal to 0.
2x^2+3=0, subtract 3
2x^2=-3, divide by 2(I don't know where I went wrong here, but I still got the right answer?)
x^2=-3/2 (you should get an imaginary number, but I know that's not the case. Assume the number is positive?)
[tex]x = - \sqrt{6} \div 2[/tex]
Do the same with the next, and you should get the square root of 3.
