Question

You just got a free ticket for a boat ride, and you can bring along 3 friends! Unfortunately, you have 6 friends who want to come along.
How many different groups of friends could you take with you?

Answer 1

Answer:

Assuming that your own ticket is already secured.

From the 5 friends you can only choose 3.

The order in which these friends are chosen is not relevant. So this is a Combination problem.

Where the order is relevant the problem becomes a Permutation problem! 

So the answer is 5 combination 3.          =  ⁵C₃

⁵C₃  =  (5 * 4 * 3) / ( 3 * 2 * 1) = 20

You can take 10 groups of any 3 of your 6 friends.

Hope this helps! have a spooky day!

Brainly?

Answer 2

Answer:

we can have 20 options or 20 different groups of friends

Step-by-step explanation:

Given that:

• Number of friends: 6
• Number of friends you can bring along: 3

How many different groups of friends could you take with you? From that question, we can know that it is a Permutation problem.

We have:

$C_{6} ^{3}$ = 20

So we can have 20 options or 20 different groups of friends

Hope it will find you well.