Answer:
[tex]\large \boxed{\text{1.00 cm}^{-3}}[/tex]
Explanation:
[tex]\begin{array}{rcl}\text{Density}&=& \dfrac{\text{Mass}}{\text{Volume}}\\\\&=& \dfrac{m}{V}\\\\10.5 \text{ g $\cdot$ cm$^{-3}$}& = & \dfrac{\text{10.5 g}}{V}\\\\10.5 V \text{ cm$^{-3}$} & = & 10.5\\V & = & \dfrac{10.5}{10.5 \text{ cm$^{-3}$}}\\\\& = & \mathbf{1.00} \textbf{ cm}^{\mathbf{-3}}\\\end{array}\\\text{The volume of silver will be } \large \boxed{\textbf{1.00 cm}^{\mathbf{-3}}}[/tex]