Answer:
10y = 13x + 139
Step-by-step explanation:
Points (-5, -3) and (-15, -16) are the two points through which Line 1 passes.
So, the slope of the line 1 is [tex]\frac{-3-(-16)}{-5-(-15)} =\frac{13}{10}[/tex]
Now, the slope of the parallel straight line i.e. line 2 will be same as line 1 i.e. [tex]\frac{13}{10}[/tex]
Let us assume that the equation of line 2 is
[tex]y= \frac{13}{10} x+c[/tex] {Where c is a constant} ....... (1)
Now, line 2 passes through the point (-13, 17). Hence, this point will satisfy equation (1).
So, [tex]17= \frac{13}{10} (-13)+c[/tex]
⇒ [tex]c=\frac{139}{10}[/tex]
Therefore, the equation of line 2 will be
[tex]y=\frac{13}{10} x+\frac{139}{10}[/tex]
⇒ 10y = 13x + 139 (Answer)
