Question

find the 30th term of an arithmetic progression 5,1015,20​

Answer 1

Answer:

150

Step-by-step explanation:

The n th term of an arithmetic progression is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here d = 10 - 5 = 5 and a₁ = 5, hence

$a_{30}$ = 5 + (29 × 5) = 5 + 145 = 150