Consider three consecutive positive integers. If the third number is subtracted from the the sum of the first two numbers, the difference is 10. Find the number.

Respuesta :

The three consecutive positive integers are 11 , 12 , 13

Step-by-step explanation:

Lets explain the meaning of consecutive integers

1. Consecutive integers are the integers that follow each other in order

2. The difference between each two consecutive integers is 1

Ex: 1 , 2 , 3 , 4 , ........ are consecutive integers

     2 , 4 , 6 , 8 , ........ are consecutive even integers

     1 , 3 , 5 , 7 , .......... are consecutive odd integers

∵ There are three consecutive positive integers

- Assume that the first positive integer is x

∵ The 1st positive integer is x

∴ The 2nd positive integer is x + 1

∴ The 3rd positive integer is x + 2

If the third number is subtracted from the the sum of the first two

numbers, the difference is 10

∵ The sum of the first two numbers = x + x + 1 = 2x + 1

∵ The 3rd number subtracted from the sum of the first two numbers

∴ The difference = (2x + 1) - (x + 2)

- Simplify it

∴ The difference = 2x + 1 - x - 2

- Add like terms

∴ The difference = (2x - x) + (1 - 2)

∴ The difference = x + (-1)

∴ The difference = x - 1

∵ The difference = 10

- Equate the difference

∴ x - 1 = 10

- Add 1 for both sides

∴ x = 11

∵ x represents the first numbers

∴ The numbers are 11 , 12 , 13

The three consecutive positive integers are 11 , 12 , 13

Learn more:

You can learn more about consecutive numbers in brainly.com/question/5496711

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