The equation 3y = x + 1 would graph a line parallel to 3y = x + 5 ⇒ 1st
Step-by-step explanation:
Parallel lines have same slopes and different y-intercepts
To find which equation would graph a line parallel to 3y = x + 5
1. Put the equation in the form of y = mx + c
2. m is the slope of the line and c is the y-intercept
3. Look for the equation which has the same values of m and different
values of c
∵ 3y = x + 5
- Divide each term of the equation by 3 to put the equation in the
form of y = mx + c
∴ y = [tex]\frac{1}{3}[/tex] x + [tex]\frac{5}{3}[/tex]
∴ m = [tex]\frac{1}{3}[/tex]
∴ c = [tex]\frac{5}{3}[/tex]
The first answer:
∵ 3y = x + 1
- Divide each term of the equation by 3
∴ y = [tex]\frac{1}{3}[/tex] x + [tex]\frac{1}{3}[/tex]
∴ m = [tex]\frac{1}{3}[/tex]
∴ c = [tex]\frac{1}{3}[/tex]
∵ The two equations have same slope m = [tex]\frac{1}{3}[/tex]
∵ The two equations have different y-intercepts c = [tex]\frac{5}{3}[/tex]
and c = [tex]\frac{1}{3}[/tex]
∴ 3y = x + 5 and 3y = x + 1 represent two parallel lines
The equation 3y = x + 1 would graph a line parallel to 3y = x + 5
Learn more:
You can learn more about slope of a line in brainly.com/question/12954015
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