Question

40.1 g of liquid benzene initially at 37.40 degree Celsius, how many kcal if energy must be added to the sample to raise the temperature to 94.60 degrees celsius?

Answer 1

Answer:

The answer to your question is: Q = 0.096 kcal

Explanation:

Data

mass = 40.1 g = 0.0401 kg

T1 = 37.4

Q = ? kcal

T2 = 94.6 °C

Cp = 0.042 kcal/kg°C

Formula

                Q = mCΔT

                Q = 0.0401 x 0.042 x (94.6 - 37.4)

                Q = 0.096 kcal

               

Answer 2

Q is the answer beacsuse