Respuesta :
Answer:
Part A) [tex]D=70T[/tex]
Part B) [tex]D=105\ miles[/tex]
Step-by-step explanation:
Par A) Write an equation that relates the distance D this car travels in T hours
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]y/x=k[/tex] or [tex]y=kx[/tex]
The speed is a proportional relationship between the distance and the time
Let
D ----> the distance in miles
T ----> the time in hours
so
[tex]D=kT[/tex]
In this problem the constant of proportionality k represent the speed of the car in miles per hour
we have
[tex]k=70\ mi/h[/tex]
substitute
[tex]D=70T[/tex]
Part B) Use the equation to find the distance the car travels between 3:30 p.m. and 5:00 p.m
we know that
The time between 3:30 p.m. and 5:00 p.m is equal to
5:00 p.m-3:30 p.m=1.5 hours
so
For T=1.5 h
substitute in the equation and solve for D
[tex]D=70(1.5)[/tex]
[tex]D=105\ miles[/tex]
Formula: Distance= Speed * Time
Distance= 70 * T
T=1.5 hrs
D= 70*1.5
D=130 miles