Question

If 100.0J are added to 20g of water at 30.0c what will be the final temperature

Answer 1

Answer:

31.19

Explanation:

H= MC x Temperature change

100 = (20/1000) x 4200 x A

100= 84A

A= 1.19

A=X-30

1.19=X-30

X=30+1.19

X=31.19