Question

Teddy is delivering boxes of paper to each floor of an office building. Each box weighs 56
pounds, and Teddy himself weighs 140 pounds. If the maximum capacity of an elevator is 2,000
pounds, or one ton, which of the following inequalities describes how many b boxes Teddy can
safely take on each elevator trip without going over the capacity?
@ 02 32
Ⓡ 0532
IV
0 0533

Answer 1

Answer: He would be able

To hold 3 boxes

Step-by-step explanation: if you add his weight with the boxes you would get under 200 pounds,, but if you go any more boxes, it would be over 200 pounds

Answer 2

Answer:

Givens

• Each box weighs 56 pounds.
• Teddy weighs 140 pounds.
• The maximum capacity of the elevator is 2,000 pounds.

So, we have 56 pounds per box, this can be expressed as

$56b$ , where $b$ represents boxes.

This problem is about a restriction as maximum, that means we need to use the inequality sign $\leq$, which represents all values accepted.

Taking in count all those details, the inequality expression is

$56b+140\leq 2000$

Because the sum of the total weght must be equal or under 2000.

Then, we solve for $b$

$56b+140\leq 2000\\56b\leq 2000-140\\b \leq \frac{1860}{56}\\ b\leq 33$

Therefore, Teddy can deliver 33 boxes of paper, because that's the maximum allowed in an elevator.