Answer:
Q = 750 cal
Explanation:
Given data:
Mass of water = 50.0 g
Change in temperature = 15.0°C
Amount of heat = ?
Solution:
The heat capacity of water is 4.186 j/g.°C
Formula:
Q = m . c .ΔT
Q = is amount of heat released or absorbed
m= mass of given substance
c = specific heat capacity of substance
ΔT = Change in temperature
Now we will put the values in formula.
Q = m . c .ΔT
Q = 50.0 g × 4.186 j/g.°C × 15.0°C
Q = 3139.5 J
Q = 3139.5 /4184
Q = 0.750 KCal
0.750 × 1000 = 750 cal
Q = 750 cal
