Answer:
a) 23.0 m
b) -11.2 m
c) 177 m/s
d) 4.65 s
Explanation:
Given:
v₀ = 22.8 m/s
a = -9.8 m/s²
a) Find Δx when t = 3.18 s.
Δx = v₀ t + ½ at²
Δx = (22.8 m/s) (3.18 s) + ½ (-9.8 m/s²) (3.18 s)²
Δx = 23.0 m
b) Find Δx when t = 5.10 s.
Δx = v₀ t + ½ at²
Δx = (22.8 m/s) (5.10 s) + ½ (-9.8 m/s²) (5.10 s)²
Δx = -11.2 m
c) Find v when Δx = 17.5 m.
v² = v₀² + 2aΔx
v² = (22.8 m/s)² + 2 (-9.8 m/s²) (17.5 m)
v = 177 m/s
d) Find t when Δx = 0 m.
Δx = v₀ t + ½ at²
(0 m) = (22.8 m/s) t + ½ (-9.8 m/s²) t²
t = 4.65 s
