Answer:
The mass of ice is 1,06 kg
Explanation:
Formula for calorimetry: Q = m . C . ΔT
Formula for phase transition, with latent heat: Q = L . m
m . C . ΔT + L . m + m . C . ΔT = 4490 kJ
m . 2,01 J/g°C (0° - (-12,1°C) + 334 J/g . m + m . 4,186 J/g°C . (15,2°C - 0°C)
Our unknown value is mass
You should look for latent heat of Ice and of course, specific heat of water.
Those are constant and they are known.
As the units are in J, and the heat for the process is in Kj we have to convert the final number into J
4490kJ . 1000 = 449000 J
m. 2,01 J/g°C (0°-(-12,1°C) + 334 J/g .m +m .4,186 J/g°C .(15,2°C - 0°C) = 449000 J
m. 24,321 J/g + 334 J/g .m + 63,62 J/g . m = 449000 J
421,94 J/g . m = 449000 J
m = 449000 J /421,94 g/J = 1064,1 g ---->1,06 kg
