Question

a motorcyclist after 12 seconds, acquires a speed of 9 m/s and 6 seconds later achieves a speed of 15m/s. As it travels along a straight line over a sloping street.

What is the distance?

Answer 1

Answer:

72 m

Explanation:

Assuming the motorcyclist is travelling at constant acceleration, we can find the distance travelled by using the following suvat equation:

$d=(\frac{u+v}{2})t$

where

d is the distance travelled

u is the initial velocity

v is the final velocity

t is the time interval

In this problem we have

u = 9 m/s

v = 15 m/s

t = 6 s (we are only interested in the time interval in which the velocity changes from 9 m/s to 15 m/s)

Substituting we find

$d=(\frac{9+15}{2})(6)=72 m$