Answer:
Let Jody's Age be X
Then Jody's Brother age is: 2x - 3
Total is: (2x - 3) + x = 30
Now we solve for x
2x - 3+ x = 30
3x - 3 = 30
3x = 30 + 3
3x = 33
x = 33/3
x = 11
Therefore the age of Jody's Brother is (2×11) - 3 = 19
Algebraic equations are equations that have unknown variables. These unknown variables can be represented with any letter of the alphabet.
The age of Jody's brother after solving the algebraic equation is 19 years.
Let's represent:
Jody's age = a
Jody's brother's age = b
Jody’s older brother is only three years less than twice jody’s age.
This is represented mathematically using an algebraic equation :
b = 2a - 3
The sum of their ages is 30. This can be written as:
a + b = 30
:a + 2a - 3 = 30
We add 3 to both sides
a + 2a - 3 + 3 = 30+ 3
3a = 33
Divide both sides by 3
3a/3 = 33/3
a = 11
Hence, Jody's age is 11 years.
Solving for Jody's brother's age:
2a - 3
2 x 11 - 3
22 - 3
= 19 years
Therefore, the age of Jody's brother is 19
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