Given that sin theta=0.3262 and theta is in quadrant I,find sin theta/2
![Given that sin theta03262 and theta is in quadrant Ifind sin theta2 class=](https://us-static.z-dn.net/files/df6/314f768b2ecf16ccf84264e208a3b779.jpg)
Answer:
The answer to your question is: sin Ф = 0.1654
Step-by-step explanation:
Data
sin Ф = 0.3262
Process
sin⁻¹ Ф = Ф = 19.034°
Ф/2 = 9.519°
sin Ф/2 = sin (9.519) = 0.1654
Answer:
sin θ/2 = 0.1654
Step-by-step explanation:
sin²θ + cos²θ = 1
cos²θ = 1 - sin²θ
cos²θ = 1 - (0.3262)²
cos²θ = √1 - (0.3262)²
cosθ = 0.9453
sin θ/2 = √1-cosθ/2
sin θ/2 = √1-0.9453/2
sin θ/2 = √0.02735
sin θ/2 = 0.1654
Best of Luck!