A 24kg child descends a slide 5m high and reaches the bottom with a speed of 2.8m/s. How much thermal energy due to friction was generated in this process?

Respuesta :

Answer:

1101.96 J

Explanation:

Potential energy at top = mgh = 24*10*5 = 1200J

Kinetic energy at bottom = 1/2*m*v² = 0.5*24*(2.8)²= 94.08 J

Loss of energy = 1200 J - 98.04 J

                         = 1101.96 J

Thermal energy due to friction =1101.96 J

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