Question

8. An object accelerates at a rate of -3.2 m/s2 to a velocity of 5 m/s over a time of 10 s. What was its initial velocity

Answer 1

Given, a = -3.2m/s²

v = 5m/s

t = 10s

u = ?

Using kinematic equation,

v = u + at

5 = u -3.2* 10

5 = u - 32

u = 32 + 5

u = 37 m/s

Answer 2

Here, we are required to determine the initial velocity of the object.

The initial velocity of the object is; u = 37m/s

By definition, the acceleration of an object the rate of change of its velocity with time.

Mathematically, this can be written as;

a = (v -u)/t

• where v = final velocity

• u = initial velocity

• t = time over which the change in velocity occurs.

This also forms the basis for the kinematic equation as follows;

v = u + at

Therefore,

• 5m/s = u + (-3.2 × 10)

• 5m/s = u - 32m/s

• Therefore, u = (32 + 5)m/s.

The initial velocity of the object is, u = 37m/s

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