Question

If 50.0g of CH3OH (MM = 32.04 g/mol) are dissolved in 500.0 mL of solution, what is the concentration of CH3OH in the solution?

Answer 1

$25 \div 32.04 =$
answer is 0.78027

Answer 2

Answer : The concentration of $CH_3OH$ in the solution is 3.12 M.

Explanation : Given,

Mass of $CH_3OH$ = 50.0 g

Volume of solution = 500.0 mL

Molar mass of $CH_3OH$ = 32.04 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of }CH_3OH\times 1000}{\text{Molar mass of }CH_3OH\times \text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{50.0g\times 1000}{32.04g/mole\times 500.0mL}=3.12mole/L=3.12M$

Therefore, the concentration of $CH_3OH$ in the solution is 3.12 M.