Answer:
New volume is 295.61 mL
Explanation:
According Charles's law, at constant pressure the volume of a fixed mass of a gas and its absolute temperature are directly proportional.
Mathematically;
[tex]V\alpha T[/tex]
[tex]V=kT[/tex]
When the variables are varied then we have a constant equivalent to;
[tex]K=\frac{V1}{T1} =\frac{V2}{T2}[/tex]
In this case, we are given;
Initial volume, V1 = 320.0 ML
Initial temperature, T1 = 55 °C or 328 K
New temperature, T2 = 30 °C or 303 K
We are required to calculate the new volume
This can be done by replacing the values of each variable in the equation;
[tex]\frac{V1}{T1} =\frac{V2}{T2}[/tex]
we get;
[tex]\frac{320}{328} =\frac{V2}{303}[/tex]
[tex]V2 =(\frac{320}{328})(303)[/tex]
[tex]V2 = 295.609 mL[/tex]
= 295.61 mL (2 d.p.)
Thus; the new volume is 295.61 mL